(x^2+2x+1)*(x^2+1)=0

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Solution for (x^2+2x+1)*(x^2+1)=0 equation: 


Simplifying
(x2 + 2x + 1)(x2 + 1) = 0

Reorder the terms:
(1 + 2x + x2)(x2 + 1) = 0

Reorder the terms:
(1 + 2x + x2)(1 + x2) = 0

Multiply (1 + 2x + x2) * (1 + x2)
(1(1 + x2) + 2x * (1 + x2) + x2(1 + x2)) = 0
((1 * 1 + x2 * 1) + 2x * (1 + x2) + x2(1 + x2)) = 0
((1 + 1x2) + 2x * (1 + x2) + x2(1 + x2)) = 0
(1 + 1x2 + (1 * 2x + x2 * 2x) + x2(1 + x2)) = 0
(1 + 1x2 + (2x + 2x3) + x2(1 + x2)) = 0
(1 + 1x2 + 2x + 2x3 + (1 * x2 + x2 * x2)) = 0
(1 + 1x2 + 2x + 2x3 + (1x2 + x4)) = 0

Reorder the terms:
(1 + 2x + 1x2 + 1x2 + 2x3 + x4) = 0

Combine like terms: 1x2 + 1x2 = 2x2
(1 + 2x + 2x2 + 2x3 + x4) = 0

Solving
1 + 2x + 2x2 + 2x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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